题目 For two rational numbers, your task is to implement the basic arithmetics, that is, to calculate their sum, difference, product and quotient. Input Specification: Each input file contains one test case, which gives in one line the two rational numbers…
辗转相除法求最大公约数:
int gcd(int a,int b)
{return b0?a:gcd(b,a%b);
}原理:
gcd(a,b) gcd(b,a % b)
gcd(a,0) a简要证明: 证明:gcd(a,b) gcd(b,a % b) 将 a 表示为 kb r,(a、b、k、r 均是正整…
写一段代码,求出两个整数的最大公约数,尽量优化算法的性能。 (1)暴力枚举: 从较小整数的一半开始,试图找到一个合适的整数 i,看看这个整数能否被 a 和 b 同时整除。
public static int getGrea…
文章目录 一、题目二、题解 一、题目
1071. Greatest Common Divisor of Strings
For two strings s and t, we say “t divides s” if and only if s t … t (i.e., t is concatenated with itself one or more times).
Given two strings str1 and str2, return the l…
作者刘文涛 转载请注明出处
一、简单介绍
1.什么是GCD
Grand Central Dispatch是由苹果开发的一个多核编程的解决方案。iOS4.0才能使用,是替代NSThread, NSOperation的高效和强大的技术。 苹果官方给出的解释:GCD是异步执行任务的技术之…
假设: ab k......r证明辗转相除法,即证gcd(a,b) gcd(b,r),可以分为两个步骤:1、令c gcd(a,b),证明 c 也是 …
扩展欧几里得算法是欧几里得算法(又叫辗转相除法)的扩展。通常谈到最大公因子时, 我们都会提到一个非常基本的事实: 给予二整数 a 与 b, 必存在有整数 x 与 y 使得ax by gcd(a,b)。因此,有两个数a,b,对它们进行辗转相除法&#…
题目
Given N rational numbers in the form “numerator/denominator”, you are supposed to calculate their sum.
Input Specification:
Each input file contains one test case. Each case starts with a positive integer N (<100), followed in the next line N …
GCD
Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 4549 Accepted Submission(s): 1630 Problem DescriptionGive you a sequence of N(N≤100,000)integers : a1,...,an(0<ai≤1000,000,000). There ar…
gcd与lcm
gcd(最大公因数)
long long int gcd(long long int a,long long int b)
{return b?gcd(b,a%b):a;//相当于 b!0执行;前 b0执行:后 //欧几里得算法 递归
}lcm(最小公倍数)
long long int lcm(long long int…